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MHT CET 2024 (10 May, Shift 2) · Thermal Radiation: Black Body, Stefan & Wien

Thermal Radiation: Black Body, Stefan & Wien question from MHT CET 2024 (10 May, Shift 2)

Q61MHT CET 2024 · 10 MAY · SHIFT 2Medium

Thermal Radiation: Black Body, Stefan & Wien

Rate of radiation by a black body is ' R ' at temperature 'T'. Another body has same area but emissivity is 0.2 and temperature 3T. Its rate of radiation is

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Answer: (c)

  1. Rate of radiation P=eσAT4P = e\sigma A T^4; for the black body R=σAT4R = \sigma A T^4.
  2. P′=0.2 σA(3T)4=0.2×81RP' = 0.2\,\sigma A (3T)^4 = 0.2 \times 81 R
  3. P′=16.2RP' = 16.2R
  4. So the answer is (c) (16.2)R(16.2)R.
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