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MHT CET 2021 (21 Sep, Shift 2) · Bohr Model: Orbits, Speed & Angular Momentum

Bohr Model: Orbits, Speed & Angular Momentum question from MHT CET 2021 (21 Sep, Shift 2)

Q91MHT CET 2021 · 21 SEP · SHIFT 2Medium

Bohr Model: Orbits, Speed & Angular Momentum

Ratio centripetal acceleration for an electron revolving in 3rd and 5th Bohr orbit of hydrogen atom is

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Answer: (b)

  1. Centripetal acceleration a=v2ra = \frac{v^2}{r} with v∝1nv \propto \frac{1}{n} and r∝n2r \propto n^2.
  2. So a∝1/n2n2=1n4a \propto \frac{1/n^2}{n^2} = \frac{1}{n^4}.
  3. a3a5=5434=62581\frac{a_3}{a_5} = \frac{5^4}{3^4} = \frac{625}{81}
  4. So the answer is (b) 625:81625 : 81.
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