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Hydrogen Spectrum & Spectral Series question from NEET 2013

Q57NEET 2013Medium

Hydrogen Spectrum & Spectral Series

Ratio of longest wave lengths corresponding to Lyman and Balmer series in hydrogen spectrum is

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Answer: (c)

  1. Lyman longest (2→12 \to 1): 1λL=3R4\frac{1}{\lambda_L} = \frac{3R}{4}
  2. Balmer longest (3→23 \to 2): 1λB=5R36\frac{1}{\lambda_B} = \frac{5R}{36}
  3. λLλB=5/363/4=527\frac{\lambda_L}{\lambda_B} = \frac{5/36}{3/4} = \frac{5}{27}
  4. So the answer is (c) 527\frac{5}{27}.
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