Ratio of longest wavelength corresponding to Lyman and Balmer series… | MHT CET 2023 (14 May, Shift 2)

Q30MHT CET 2023 · 14 MAY · SHIFT 2Medium

Hydrogen Spectrum & Spectral Series

Ratio of longest wavelength corresponding to Lyman and Balmer series in hydrogen spectrum is

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Answer: (c)

Longest wavelength = first line of each series.
Lyman: $\lambda_L = \frac{4}{3R}$ ; Balmer: $\frac{1}{\lambda_B} = R\left(\frac{1}{4} - \frac{1}{9}\right) = \frac{5R}{36}$ , so $\lambda_B = \frac{36}{5R}$ .
$\frac{\lambda_L}{\lambda_B} = \frac{4}{3} \times \frac{5}{36} = \frac{5}{27}$ .
So the answer is (c) $\frac{5}{27}$ .

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