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MHT CET 2024 (3 May, Shift 1) · Moment of Inertia & Radius of Gyration

Moment of Inertia & Radius of Gyration question from MHT CET 2024 (3 May, Shift 1)

Q64MHT CET 2024 · 3 MAY · SHIFT 1Easy

Moment of Inertia & Radius of Gyration

Ratio of radius of gyration of a circular disc to that of circular ring each of same mass and radius around their respective axes is

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Answer: (d)

  1. Disc: I=MR22⇒Kd=R2I = \frac{MR^2}{2} \Rightarrow K_d = \frac{R}{\sqrt{2}}.
  2. Ring: I=MR2⇒Kr=RI = MR^2 \Rightarrow K_r = R.
  3. Kd:Kr=12:1=1:2K_d : K_r = \frac{1}{\sqrt{2}} : 1 = 1 : \sqrt{2}
  4. So the answer is (d) 1:21 : \sqrt{2}.
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