Region I and II are separated by a spherical surface of radius 25 cm… | JEE Main 2021 (20 Jul, Shift 1)

Q74JEE Main 2021 · 20 JUL · SHIFT 1Medium

Spherical Surfaces & Thin Lenses

Region I and II are separated by a spherical surface of radius 25 cm. An object is kept in region I at a distance of 40 cm from the surface. The distance of the image from the surface is:

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Answer: (d)

Light goes from region I ( $\mu_1 = 1.25$ ) to II ( $\mu_2 = 1.4$ ). Centre C is on the object side, so $R = -25$ cm; $u = -40$ cm.
$\frac{1.4}{v} - \frac{1.25}{-40} = \frac{1.4 - 1.25}{-25}$
$\frac{1.4}{v} = -0.006 - 0.03125 = -0.03725$
$v = -37.58$ cm (virtual image in region I).
So the answer is (d) 37.58 cm.

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