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JEE Main 2012 (AIEEE) · Errors in Measurement

Errors in Measurement question from JEE Main 2012 (AIEEE)

Q106JEE Main 2012 · AIEEEDifficult

Errors in Measurement

Resistance of a given wire is obtained by measuring the current flowing in it and the voltage difference applied across it. If the percentage errors in the measurement of the current and the voltage difference are 3% each, then error in the value of resistance of the wire is

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Answer: (a)

  1. R=VIR = \dfrac{V}{I}, so ΔRR=ΔVV+ΔII\dfrac{\Delta R}{R} = \dfrac{\Delta V}{V} + \dfrac{\Delta I}{I} (errors always add).
  2. =3%+3%=6%= 3\% + 3\% = 6\%
  3. So the answer is (a) 6%6\%.
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