Resistance of a potentiometer wire is 2 Ω/m. A cell of e.m.f. 1.5 V balances at 300 cm. The current through the wire is (a) 2.5 mA (b) 7.5 mA (c) 250 mA (d) 750 mA

Answer: (c). k = E/l = 1.5/3 = 0.5 V/m. Also k = I × (resistance per metre), so I = 0.5/2 = 0.25 A. So the answer is (c) 250 mA.

Resistance of a potentiometer wire is 2 Ω/m. A cell of e.m.f. 1.5 V… | MHT CET 2023 (12 May, Shift 1)

Q37MHT CET 2023 · 12 MAY · SHIFT 1Easy

Potentiometer

Resistance of a potentiometer wire is $2\ \Omega/\text{m}$ . A cell of e.m.f. $1.5\text{ V}$ balances at $300\text{ cm}$ . The current through the wire is

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Answer: (c)

$k = \frac{E}{l} = \frac{1.5}{3} = 0.5\ \text{V/m}$ .
Also $k = I \times (\text{resistance per metre})$ , so $I = \frac{0.5}{2} = 0.25\ \text{A}$ .
So the answer is (c) 250 mA.

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Potentiometer question from MHT CET 2023 (12 May, Shift 1)

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