Resistance of a wire at 0, 100 and t is found to be 10 Ω, 10.2 Ω and 10.95 Ω respectively. The temperature t in Kelvin scale is _________. Numerical answer type. Work it out, then open the answer.

Answer: 748. Rt = R₀(1+α t): R₀α = (10.2-10)/100 = 0.002 Ω/° C. 10.95 - 10 = 0.002 t ⇒ t = 475° C T = 475 + 273 = 748 K.

Resistance of a wire at 0, 100 and t is found to be 10 Ω, 10.2 Ω and… | JEE Main 2024 (8 Apr, Shift 1)

Q12JEE Main 2024 · 8 APR · SHIFT 1Medium

Ohm's Law, Resistivity & Temperature

Resistance of a wire at $0^\circ\text{C}, 100^\circ\text{C}$ and $t^\circ\text{C}$ is found to be $10\ \Omega, 10.2\ \Omega$ and $10.95\ \Omega$ respectively. The temperature $t$ in Kelvin scale is _________.

Numerical answer type. Work it out, then open the answer.

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Answer: 748

$R_t = R_0(1+\alpha t)$ : $R_0\alpha = (10.2-10)/100 = 0.002\ \Omega/^\circ$ C.
$10.95 - 10 = 0.002\,t \Rightarrow t = 475^\circ$ C
$T = 475 + 273 = 748$ K.

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