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MHT CET 2026 (13 Apr, Shift 2) · Wheatstone Bridge & Metre Bridge

Wheatstone Bridge & Metre Bridge question from MHT CET 2026 (13 Apr, Shift 2)

Q4MHT CET 2026 · 13 APR · SHIFT 2Medium

Wheatstone Bridge & Metre Bridge

Resistances are joint as shown in the figure. In the balanced condition, the current $I$ drawn from the battery is

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Answer: (c)

Balanced bridge ( $10/10 = 30/30$ ): no current in G, remove it.
Path ABC: $10 + 10 = 20\ \Omega$ ; path ADC: $30 + 30 = 60\ \Omega$
$R_{eq} = \dfrac{20 \times 60}{80} = 15\ \Omega$
$I = \dfrac{3}{15} = 0.2$ A
So the answer is (c) $0.2$ A.

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