Student Login

Home›Chapters›Oscillations PYQs›Simple Pendulum›Question 16

NEET 2026 · Simple Pendulum

Simple Pendulum question from NEET 2026

Q16NEET 2026Medium

Simple Pendulum

Savitha, a XI standard student, while conducting an experiment to determine the effective length of a simple pendulum $L$ , notes down the data of time taken to complete 30 oscillations as 60 s and hence calculates the length of the simple pendulum as: (Take $\pi^{2} = 9.8$ , and $g = 9.8\text{ m/s}^{2}$ )

Show answer and solution

Answer: (d)

Period $T = \frac{60}{30} = 2\text{ s}$ .
$T = 2\pi\sqrt{L/g} \Rightarrow L = \frac{gT^2}{4\pi^2} = \frac{9.8 \times 4}{4 \times 9.8}$ .
So the answer is (d) $1\text{ m}$ .

Report a mistake

More questions on Simple Pendulum

An oscillating pendulum suspended from the roof of a lift which is at rest has time…MHT CET 2026 (11 Apr, Shift 2)
The ratio of the frequencies of two simple pendulums is 4: 3 at the same place. The ratio…MHT CET 2025 (26 Apr, Shift 1)
The length of the simple pendulum is made 3 times the original length. If ' T ' is its…MHT CET 2025 (21 Apr, Shift 2)
At a place, the length of the oscillating simple pendulum is made 1/4 times keeping…MHT CET 2025 (26 Apr, Shift 1)
If the length of the oscillating simple pendulum is made 1/3 times the original keeping…MHT CET 2025 (19 Apr, Shift 2)
Given below are two statements: one is labelled as Assertion (A) and the other is…JEE Main 2025 (29 Jan, Shift 1)
Given below are two statements. One is labelled as Assertion (A) and the other is…JEE Main 2025 (22 Jan, Shift 2)
The time period of a simple pendulum inside a stationary lift is √(3) second. When the…MHT CET 2025 (19 Apr, Shift 1)