Select the correct statement out of the following (a) Acceleration due to gravity decreases as we go up or down from earth's surface. (b) Acceleration due to gravity is same at a height 'h' and depth 'd' from earth's surface, if h = d. (c) Acceleration due to gravity at 640 km above the earth surface decreases by 10% of its value at earth's surface (earth's radius is 6400 km) (d) There is reduction in acceleration due to gravity at poles due to rotation of earth as the poles are lying on the axis of rotation and do not revolve.

Answer: (a). (a) True: gh = (gR²)/((R+h)²) < g and gd = g(1-d/R) < g. (b) False: for small heights gh ≈ g(1-2h/R) but gd = g(1-d/R), so they differ when h = d. (c) False: gh = (g)/((1.1)²) ≈ 0.83g, a decrease of about 17%, not 10%. (d) False: g' = g - ω² Rcos ²λ; at the poles λ = 90°, so rotation causes no reduction there. So the answer is (a).

Select the correct statement out of the following | MHT CET 2026 (20 Apr, Shift 2)

Q5MHT CET 2026 · 20 APR · SHIFT 2Easy

Acceleration Due to Gravity

Select the correct statement out of the following

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Answer: (a)

(a) True: $g_h = \frac{gR^2}{(R+h)^2} < g$ and $g_d = g\left(1-\frac{d}{R}\right) < g$ .
(b) False: for small heights $g_h \approx g\left(1-\frac{2h}{R}\right)$ but $g_d = g\left(1-\frac{d}{R}\right)$ , so they differ when $h = d$ .
(c) False: $g_h = \frac{g}{(1.1)^2} \approx 0.83g$ , a decrease of about $17\%$ , not $10\%$ .
(d) False: $g' = g - \omega^2 R\cos^2\lambda$ ; at the poles $\lambda = 90^\circ$ , so rotation causes no reduction there.
So the answer is (a).

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Acceleration Due to Gravity question from MHT CET 2026 (20 Apr, Shift 2)

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