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JEE Main 2018 · Moment of Inertia & Radius of Gyration

Moment of Inertia & Radius of Gyration question from JEE Main 2018

Q170JEE Main 2018Medium

Moment of Inertia & Radius of Gyration

Seven identical circular planar disks, each of mass M and radius R are welded symmetrically as shown. The moment of inertia of the arrangement about the axis normal to the plane and passing through the point P is:

Figure

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Answer: (a)

  1. About O: centre disc MR22\frac{MR^2}{2}; each outer disc MR22+M(2R)2=92MR2\frac{MR^2}{2} + M(2R)^2 = \frac{9}{2}MR^2.
  2. IO=12MR2+6×92MR2=552MR2I_O = \frac{1}{2}MR^2 + 6 \times \frac{9}{2}MR^2 = \frac{55}{2}MR^2
  3. P is 3R3R from O, total mass 7M7M: IP=552MR2+7M(3R)2I_P = \frac{55}{2}MR^2 + 7M(3R)^2
  4. IP=55+1262MR2=1812MR2I_P = \frac{55 + 126}{2}MR^2 = \frac{181}{2}MR^2, so the answer is (a).
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