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MHT CET 2023 (10 May, Shift 1) · Moment of Inertia & Radius of Gyration

Moment of Inertia & Radius of Gyration question from MHT CET 2023 (10 May, Shift 1)

Q109MHT CET 2023 · 10 MAY · SHIFT 1Difficult

Moment of Inertia & Radius of Gyration

Seven identical discs each of mass MM and radius RR are arranged in a hexagonal plane pattern so as to touch each neighbour disc as shown in the figure. The moment of inertia of the system of seven discs about an axis passing through the centre of central disc and normal to the plane of all discs is

Figure

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Answer: (d)

  1. Central disc: MR22\frac{MR^2}{2}.
  2. Each outer disc centre is 2R2R away: MR22+4MR2=92MR2\frac{MR^2}{2} + 4MR^2 = \frac{9}{2}MR^2.
  3. I=12MR2+6×92MR2=552MR2I = \frac{1}{2}MR^2 + 6 \times \frac{9}{2}MR^2 = \frac{55}{2}MR^2
  4. So the answer is (d).
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