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JEE Main 2020 (2 Sep, Shift 1) · Rotational Kinematics & Dynamics

Rotational Kinematics & Dynamics question from JEE Main 2020 (2 Sep, Shift 1)

Q49JEE Main 2020 · 2 SEP · SHIFT 1Medium

Rotational Kinematics & Dynamics

Figure

Shown in the figure is rigid and uniform one meter long rod AB held in horizontal position by two strings tied to its ends and attached to the ceiling. The rod is of mass ‘m’ and has another weight of mass 2 m hung at a distance of 75 cm from A. The tension in the string at A is:

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Answer: (d)

  1. Take torques about B (rod length 1 m).
  2. TA(1)=mg(0.5)+2mg(0.25)T_A(1) = mg(0.5) + 2mg(0.25)
  3. TA=0.5mg+0.5mg=mgT_A = 0.5mg + 0.5mg = mg
  4. So the answer is (d) 1 mg.
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