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MHT CET 2026 (13 May, Shift 1) · Thermodynamic Processes

Thermodynamic Processes question from MHT CET 2026 (13 May, Shift 1)

Q19MHT CET 2026 · 13 MAY · SHIFT 1Medium

Thermodynamic Processes

Six moles of oxygen gas is heated from 20∘20^\circC to 35∘35^\circC at constant volume. If specific heat capacity at constant pressure is 88 cal mol−1^{-1}k −1^{-1} and gas constant is 22 cal mol−1^{-1}k −1^{-1}. The change in internal energy of the gas is

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Answer: (d)

  1. Cv=Cp−R=8−2=6 cal mol−1K−1C_v = C_p - R = 8 - 2 = 6\text{ cal mol}^{-1}\text{K}^{-1}
  2. ΔU=nCvΔT=6×6×15\Delta U = nC_v\Delta T = 6 \times 6 \times 15
  3. ΔU=540\Delta U = 540 cal, so the answer is (d).
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