Sodium has body centred packing. Distance between two nearest atoms is 3.7. The lattice parameter is (a) 4.3 (b) 3.0 (c) 8.6 (d) 6.8

Answer: (a). In BCC, nearest atoms touch along the body diagonal: d = √(3)/2a. a = (2d)/(√(3)) = (2 × 3.7)/(1.732) a ≈ 4.27 ≈ 4.3 So the answer is (a) 4.3.

Sodium has body centred packing. Distance between two nearest atoms… | NEET 2009 (AIPMT)

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${}$ Sodium has body centred packing. Distance between two nearest atoms is 3.7 $\text{\AA}$ . The lattice parameter is

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Answer: (a)

In BCC, nearest atoms touch along the body diagonal: $d = \frac{\sqrt{3}}{2}a$ .
$a = \frac{2d}{\sqrt{3}} = \frac{2 \times 3.7}{1.732}$
$a \approx 4.27 \approx 4.3\ \text{\AA}$
So the answer is (a) 4.3 $\text{\AA}$ .

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