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MHT CET 2026 (16 Apr, Shift 2) · Moment of Inertia & Radius of Gyration

Moment of Inertia & Radius of Gyration question from MHT CET 2026 (16 Apr, Shift 2)

Q22MHT CET 2026 · 16 APR · SHIFT 2Medium

Moment of Inertia & Radius of Gyration

Solid sphere is rotating about an axis as shown in figure. If the radius of the sphere is 5 cm, then radius of gyration about that axis will be $\sqrt{x}$ cm. The value of x is

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Answer: (b)

Centre of the sphere is $d = 10\text{ cm}$ from the axis; $R = 5\text{ cm}$ .
$K^2 = \frac{2}{5}R^2 + d^2 = \frac{2}{5}(25) + 100 = 110\text{ cm}^2$
So the answer is (b) $x = 110$ .

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