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MHT CET 2026 (16 Apr, Shift 2) · Moment of Inertia & Radius of Gyration

Moment of Inertia & Radius of Gyration question from MHT CET 2026 (16 Apr, Shift 2)

Q22MHT CET 2026 · 16 APR · SHIFT 2Medium

Moment of Inertia & Radius of Gyration

Solid sphere is rotating about an axis as shown in figure. If the radius of the sphere is 5 cm, then radius of gyration about that axis will be x\sqrt{x} cm. The value of x is

Figure

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Answer: (b)

  1. Centre of the sphere is d=10 cmd = 10\text{ cm} from the axis; R=5 cmR = 5\text{ cm}.
  2. K2=25R2+d2=25(25)+100=110 cm2K^2 = \frac{2}{5}R^2 + d^2 = \frac{2}{5}(25) + 100 = 110\text{ cm}^2
  3. So the answer is (b) x=110x = 110.
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