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MHT CET 2023 (14 May, Shift 2) · Stationary Waves & Vibrating Strings

Stationary Waves & Vibrating Strings question from MHT CET 2023 (14 May, Shift 2)

Q62MHT CET 2023 · 14 MAY · SHIFT 2Medium

Stationary Waves & Vibrating Strings

Sound waves of frequency 600 Hz600\text{ Hz} fall normally on a perfectly reflecting wall. The shortest distance from the wall at which all particles will have maximum amplitude of vibration is (speed of sound =300 m s−1= 300\text{ m s}^{-1})

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Answer: (b)

  1. λ=vf=300600=0.5 m\lambda = \dfrac{v}{f} = \dfrac{300}{600} = 0.5\text{ m}.
  2. A rigid wall is a displacement node; the nearest displacement antinode (maximum amplitude) is λ/4\lambda/4 away.
  3. d=0.54=18 md = \dfrac{0.5}{4} = \dfrac{1}{8}\text{ m}.
  4. So the answer is (b) 18 m\frac{1}{8}\text{ m}.
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