Speed of an electron in Bohr's 7 th orbit for Hydrogen atom is 3.6 × 10⁶ m/s. The corresponding speed of the electron in 3 rd orbit, in m/s is: (a) (1.8 × 10⁶) (b) (7.5 × 10⁶) (c) (8.4 × 10⁶) (d) (3.6 × 10⁶)

Answer: (c). vn ∝ 1/n, so v₃ = v₇ × 7/3. v₃ = 3.6 × 10⁶ × 7/3 = 8.4 × 10⁶ m/s So the answer is (c) 8.4 × 10⁶.

Speed of an electron in Bohr's 7 th orbit for Hydrogen atom is 3.6 ×… | JEE Main 2023 (30 Jan, Shift 1)

Q64JEE Main 2023 · 30 JAN · SHIFT 1Easy

Bohr Model: Orbits, Speed & Angular Momentum

Speed of an electron in Bohr's $7$ th orbit for Hydrogen atom is $3.6 \times 10^{6}\text{ m/s}$ . The corresponding speed of the electron in $3$ rd orbit, in $\text{m/s}$ is:

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Answer: (c)

$v_n \propto \frac{1}{n}$ , so $v_3 = v_7 \times \frac{7}{3}$ .
$v_3 = 3.6 \times 10^6 \times \frac{7}{3} = 8.4 \times 10^6\text{ m/s}$
So the answer is (c) $8.4 \times 10^6$ .

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Bohr Model: Orbits, Speed & Angular Momentum question from JEE Main 2023 (30 Jan, Shift 1)

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