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NEET 1997 (AIPMT) · Stationary Waves & Vibrating Strings

Stationary Waves & Vibrating Strings question from NEET 1997 (AIPMT)

Q114NEET 1997 · AIPMTEasy

Stationary Waves & Vibrating Strings

Standing waves are produced in 10 m10\text{ m} long stretched string. If the string vibrates in 5 segments and wave velocity is 20 m/s20\text{ m/s}, the frequency is

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Answer: (a)

  1. 5 segments (loops): L=5λ2L = 5\dfrac{\lambda}{2}.
  2. λ=2×105=4 m\lambda = \dfrac{2 \times 10}{5} = 4\text{ m}.
  3. f=vλ=204=5 Hzf = \dfrac{v}{\lambda} = \dfrac{20}{4} = 5\text{ Hz}.
  4. So the answer is (a) 5 Hz5\text{ Hz}.
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