Acceleration Due to Gravity question from NEET 2016 (Phase 2)

Answer: (b)

1. Inside the earth ($r < R$): $g = \frac{GM}{R^3}r$, so $g \propto r$ (straight line from the origin).
2. Outside ($r > R$): $g = \frac{GM}{r^2}$, so $g \propto \frac{1}{r^2}$ (falling curve).
3. $g$ is maximum at $r = R$.
4. So the answer is (b): straight rise up to $R$, then a $1/r^2$ fall.