Starting from the origin at time t = 0, with initial velocity 5 j ms-1, a particle moves in the x-y plane with a constant acceleration of (10i + 4j) ms-2. At time t, its coordinates are (20 m, y0 m). The values of t and y0 are, respectively: (a) 5s and 25 m (b) 2s and 18 m (c) 2s and 24 m (d) 4s and 52 m

Answer: (b). x = 12(10)t² = 5t² = 20 ⇒ t = 2 s y₀ = 5t + 12(4)t² = 10 + 8 = 18 m So the answer is (b) 2 s and 18 m.

Starting from the origin at time t = 0, with initial velocity 5 j… | JEE Main 2020 (4 Sep, Shift 1)

Q10JEE Main 2020 · 4 SEP · SHIFT 1Medium

Motion in a Plane (2-D Kinematics)

Starting from the origin at time t = 0, with initial velocity 5 $\hat{j}$ ms-1, a particle moves in the x-y plane with a constant acceleration of $\left(10\hat{i} + 4\hat{j}\right)$ ms-2. At time t, its coordinates are (20 m, y0 m). The values of t and y0 are, respectively:

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Answer: (b)

$x = \frac12(10)t^2 = 5t^2 = 20 \Rightarrow t = 2$ s
$y_0 = 5t + \frac12(4)t^2 = 10 + 8 = 18$ m
So the answer is (b) 2 s and 18 m.

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Motion in a Plane (2-D Kinematics) question from JEE Main 2020 (4 Sep, Shift 1)

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