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JEE Main 2010 (AIEEE) · Photoelectric Experiment: Intensity, Stopping Potential & Graphs

Photoelectric Experiment: Intensity, Stopping Potential & Graphs question from JEE Main 2010 (AIEEE)

Q71JEE Main 2010 · AIEEEMedium

Photoelectric Experiment: Intensity, Stopping Potential & Graphs

Statement - 11: When ultraviolet light is incident on a photocell, its stopping potential is V0V_0 and the maximum kinetic energy of the photoelectrons is KmaxK_\mathrm{max}. When the ultraviolet light is replaced by XX-rays, both V0V_0 and KmaxK_\mathrm{max} increase.

Statement - 22: Photoelectrons are emitted with speeds ranging from zero to a maximum value because of the range of frequencies present in the incident light.

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Answer: (b)

  1. X-rays have higher frequency than UV, so Kmax=hν−ϕK_{max} = h\nu - \phi and V0V_0 both increase. Statement 1 is true.
  2. The spread of speeds from zero to maximum occurs even for monochromatic light, because electrons lose different amounts of energy coming from different depths and bound states. Statement 2 is false.
  3. So the answer is (d).
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