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JEE Main 2008 (AIEEE) · Bohr Model: Orbits, Speed & Angular Momentum

Bohr Model: Orbits, Speed & Angular Momentum question from JEE Main 2008 (AIEEE)

Q117JEE Main 2008 · AIEEEDifficult

Bohr Model: Orbits, Speed & Angular Momentum

Suppose an electron is attracted towards the origin by a force kr\frac{k}{r} where ′k′'k' is a constant and ′r′'r' is the distance of the electron from the origin. By applying Bohr model to this system, the radius of the nthn^{th} orbital of the electron is found to be ′rn′'r_n' and the kinetic energy of the electron to be ′Tn′.'T_n'. Then which of the following is true?

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Answer: (b)

  1. mv2r=kr⇒mv2=k\frac{mv^2}{r} = \frac{k}{r} \Rightarrow mv^2 = k, so vv is constant.
  2. T=12mv2=k2T = \frac{1}{2}mv^2 = \frac{k}{2}, independent of nn.
  3. Bohr condition: mvr=nh2πmvr = \frac{nh}{2\pi} with constant vv, so rn∝nr_n \propto n.
  4. So the answer is (b) TnT_n independent of nn, rn∝nr_n \propto n.
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