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JEE Main 2023 (25 Jan, Shift 1) · Simple Pendulum

Simple Pendulum question from JEE Main 2023 (25 Jan, Shift 1)

Q43JEE Main 2023 · 25 JAN · SHIFT 1Easy

Simple Pendulum

T is the time period of simple pendulum on the earth's surface. Its time period becomes $x$ T when taken to a height R (equal to earth's radius) above the earth's surface. Then, the value of $x$ will be:

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Answer: (c)

At height $h = R$ : $g' = \frac{g}{(1 + h/R)^2} = \frac{g}{4}$ .
$T \propto \frac{1}{\sqrt{g}} \Rightarrow T' = T\sqrt{4} = 2T$
So the answer is (c) $x = 2$ .

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