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MHT CET 2023 (11 May, Shift 2) · AC Basics: Peak, RMS & Average Values

AC Basics: Peak, RMS & Average Values question from MHT CET 2023 (11 May, Shift 2)

Q21MHT CET 2023 · 11 MAY · SHIFT 2Easy

AC Basics: Peak, RMS & Average Values

The a.c. source of e.m.f. with instantaneous value ' $e$ ' is given by $e = 200 \sin(50t)$ volt. The r.m.s. value of current in a circuit of resistance $50\ \Omega$ is

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Answer: (b)

$I_0 = \frac{e_0}{R} = \frac{200}{50} = 4$ A
$I_{rms} = \frac{I_0}{\sqrt{2}} = \frac{4}{1.414} \approx 2.828$ A
So the answer is (b) 2.828 A.

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