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MHT CET 2026 (18 Apr, Shift 2) · Acceleration Due to Gravity

Acceleration Due to Gravity question from MHT CET 2026 (18 Apr, Shift 2)

Q10MHT CET 2026 · 18 APR · SHIFT 2Medium

Acceleration Due to Gravity

The acceleration due to gravity at a height 'h' above the surface of earth is 'ghg_h'. At the depth 90 km below the earth's surface the acceleration due to gravity is also 'ghg_h'. The value of 'h' is

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Answer: (d)

  1. Small height: gh=g(1−2hR)g_h = g\left(1 - \frac{2h}{R}\right); depth: gd=g(1−dR)g_d = g\left(1 - \frac{d}{R}\right)
  2. Equal values: 2hR=dR⇒h=d2\frac{2h}{R} = \frac{d}{R} \Rightarrow h = \frac{d}{2}
  3. h=902=45h = \frac{90}{2} = 45 km
  4. So the answer is (d) 45 km.
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