Physics Circle home Student Login

Home›Chapters›Gravitation PYQs›Acceleration Due to Gravity›Question 66

JEE Main 2023 (8 Apr, Shift 2) · Acceleration Due to Gravity

Acceleration Due to Gravity question from JEE Main 2023 (8 Apr, Shift 2)

Q66JEE Main 2023 · 8 APR · SHIFT 2Medium

Acceleration Due to Gravity

The acceleration due to gravity at height hh above the earth if h≪Rh \ll R (Radius of earth) is given by

Show answer and solution

Answer: (a)

  1. g′=g(RR+h)2=g(1+hR)−2g' = g\left(\frac{R}{R+h}\right)^2 = g\left(1+\frac{h}{R}\right)^{-2}
  2. For h≪Rh \ll R, binomial approximation: (1+x)−2≈1−2x(1+x)^{-2} \approx 1-2x
  3. g′=g(1−2hR)g' = g\left(1-\frac{2h}{R}\right)
  4. So the answer is (a).
Report a mistake

More questions on Acceleration Due to Gravity