Student Login

Home›Chapters›Gravitation PYQs›Acceleration Due to Gravity›Question 129

NEET 2003 (AIPMT) · Acceleration Due to Gravity

Acceleration Due to Gravity question from NEET 2003 (AIPMT)

Q129NEET 2003 · AIPMTMedium

Acceleration Due to Gravity

The acceleration due to gravity on the planet A is 9 times the acceleration due to gravity on planet B. A man jumps to a height of 2 m on the surface of A. What is the height of jump by the same person on the planet B?

Show answer and solution

Answer: (b)

Same take-off speed $u$ : $h = \frac{u^2}{2g} \Rightarrow h \propto \frac{1}{g}$ .
$h_B = h_A \frac{g_A}{g_B} = 2 \times 9$
So the answer is (b) $18\text{ m}$ .

Report a mistake

More questions on Acceleration Due to Gravity

A body of weight 72 N moves from the surface of earth at a height half of the radius of…NEET 2000 (AIPMT)
What will be the formula of mass of the earth in terms of g, R and G?NEET 1996 (AIPMT)
The acceleration due to gravity g and mean density of the earth ρ are related by which of…NEET 1995 (AIPMT)
The radius of earth is about 6400 km and that of mars is 3200 km. The mass of the earth…NEET 1994 (AIPMT)
The density of a planet is three times that of earth and radius 2.5 times that of earth…MHT CET 2026 (11 Apr, Shift 2)
Time period of a simple pendulum is T₁ when on the earth's surface and T₂ when taken to a…MHT CET 2026 (18 Apr, Shift 1)
The time taken by simple pendulum for one oscillation is T on earth's surface. Its time…MHT CET 2026 (16 Apr, Shift 2)
The height in terms of radius of the earth (R), at which the acceleration due to gravity…JEE Main 2026 (4 Apr, Shift 2)