The alternating voltage is given by v = v₀ sin (ω t + π/3) when will be the voltage maximum for first time? (a) T/6 (b) T/3 (c) T/2 (d) T/12

Answer: (d). Maximum when ω t + π/3 = π/2, so ω t = π/6. 2π/Tt = π/6 ⇒ t = T/12 So the answer is (d) T/12.

The alternating voltage is given by v = v₀ sin (ω t + π/3) when will… | MHT CET 2024 (16 May, Shift 1)

Q15MHT CET 2024 · 16 MAY · SHIFT 1Easy

AC Basics: Peak, RMS & Average Values

The alternating voltage is given by $v = v_0 \sin\left(\omega t + \frac{\pi}{3}\right)$ when will be the voltage maximum for first time?

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Answer: (d)

Maximum when $\omega t + \frac{\pi}{3} = \frac{\pi}{2}$ , so $\omega t = \frac{\pi}{6}$ .
$\frac{2\pi}{T}t = \frac{\pi}{6} \Rightarrow t = \frac{T}{12}$
So the answer is (d) $\frac{T}{12}$ .

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