Physics Circle home Student Login

Home›Chapters›Thermodynamics PYQs›Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation›Question 34

JEE Main 2021 (20 Jul, Shift 1) · Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation

Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation question from JEE Main 2021 (20 Jul, Shift 1)

Q34JEE Main 2021 · 20 JUL · SHIFT 1Easy

Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation

The amount of heat needed to raise the temperature of 4 moles of rigid diatomic gas from 0∘^\circ C to 50∘^\circ C when no work is done is ___________. (R is the universal gas constant).

Show answer and solution

Answer: (a)

  1. No work done means constant volume: Q=nCvΔTQ = nC_v\Delta T.
  2. Rigid diatomic: Cv=52RC_v = \frac{5}{2}R, ΔT=50\Delta T = 50 K.
  3. Q=4×52R×50=500RQ = 4 \times \frac{5}{2}R \times 50 = 500R
  4. So the answer is (a) 500R500R.
Report a mistake

More questions on Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation