The amount of work done in blowing a soap bubble such that its diameter increases from d₁ to d₂ is ( T = surface tension of soap solution) (a) 4π(d₂² - d₁²)T (b) 8π(d₂² - d₁²)T (c) π(d₂² - d₁²)T (d) 2π(d₂² - d₁²)T

Answer: (d). Two surfaces: W = 8π T (r₂² - r₁²) with r = d/2. W = 8π T (d₂² - d₁²)/(4) = 2π(d₂² - d₁²)T So the answer is (d) 2π(d₂²-d₁²)T.

The amount of work done in blowing a soap bubble such that its… | MHT CET 2025 (23 Apr, Shift 2)

Q11MHT CET 2025 · 23 APR · SHIFT 2Medium

Surface Energy & Work Done

The amount of work done in blowing a soap bubble such that its diameter increases from $d_1$ to $d_2$ is ( $T =$ surface tension of soap solution)

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Answer: (d)

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