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MHT CET 2026 (14 May, Shift 1) · Bar Magnet & Magnetic Moment

Bar Magnet & Magnetic Moment question from MHT CET 2026 (14 May, Shift 1)

Q1MHT CET 2026 · 14 MAY · SHIFT 1Easy

Bar Magnet & Magnetic Moment

The angle made by electron's orbital angular momentum ( $L$ ) with the direction of the orbital magnetic moment ( $M$ ) is

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Answer: (c)

For an orbiting charge, $\vec M = \dfrac{q}{2m}\vec L$ .
The electron has $q = -e$ , so $\vec M = -\dfrac{e}{2m_e}\vec L$ : $\vec M$ is opposite to $\vec L$ .
So the answer is (c) $180^\circ$ .

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