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MHT CET 2019 (2 May, Shift 1) · Bohr Model: Orbits, Speed & Angular Momentum

Bohr Model: Orbits, Speed & Angular Momentum question from MHT CET 2019 (2 May, Shift 1)

Q101MHT CET 2019 · 2 MAY · SHIFT 1Easy

Bohr Model: Orbits, Speed & Angular Momentum

The angle made by orbital angular momentum of electron with the direction of the orbital magnetic moment is

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Answer: (c)

$\vec{\mu} = -\frac{e}{2m}\vec{L}$ : the electron is negative, so its current is opposite to its motion.
Hence $\vec{\mu}$ and $\vec{L}$ are antiparallel.
So the answer is (c) $180^\circ$ .

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