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MHT CET 2024 (15 May, Shift 1) · Angle of Contact & Capillarity

Angle of Contact & Capillarity question from MHT CET 2024 (15 May, Shift 1)

Q36MHT CET 2024 · 15 MAY · SHIFT 1Medium

Angle of Contact & Capillarity

The angle of contact between glass and water is 0∘0^\circ and water rises in a glass capillary upto 6 cm (Surface tension of water is T). Another liquid of surface tension ' 2T2T ', angle of contact 60∘60^\circ and relative density 2 will rise in the same capillary up to (cos⁡0∘=1,cos⁡60∘=0.5)(\cos 0^\circ = 1, \cos 60^\circ = 0.5)

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Answer: (c)

  1. h=2Tcos⁡θrρg⇒h∝Tcos⁡θρh = \frac{2T\cos\theta}{r\rho g} \Rightarrow h \propto \frac{T\cos\theta}{\rho} for the same tube.
  2. h2h1=2T×0.5/2T×1/1=12\frac{h_2}{h_1} = \frac{2T \times 0.5 / 2}{T \times 1 / 1} = \frac{1}{2}
  3. h2=62=3 cmh_2 = \frac{6}{2} = 3\text{ cm}
  4. So the answer is (c) 3 cm3\text{ cm}.
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