The angle of deviation produced by a thin prism when placed in air is ' δ₁ ' and that when immersed in water is ' δ₂ '. The refractive index of glass and water are 3/2 and 4/3 respectively. The ratio δ₁: δ₂ is (a) 1: 2 (b) 2: 1 (c) 1: 4 (d) 4: 1

Answer: (d). Thin prism: δ = (nrel - 1)A δ₁ = (3/2 - 1)A = A/2; δ₂ = (9/8 - 1)A = A/8 δ₁: δ₂ = 4: 1, so the answer is (d).

The angle of deviation produced by a thin prism when placed in air is… | MHT CET 2023 (14 May, Shift 1)

Q43MHT CET 2023 · 14 MAY · SHIFT 1Medium

Prism, Dispersion & Scattering

The angle of deviation produced by a thin prism when placed in air is ' $\delta_1$ ' and that when immersed in water is ' $\delta_2$ '. The refractive index of glass and water are $\frac{3}{2}$ and $\frac{4}{3}$ respectively. The ratio $\delta_1 : \delta_2$ is

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Answer: (d)

Thin prism: $\delta = (n_{\text{rel}} - 1)A$
$\delta_1 = \left(\frac{3}{2} - 1\right)A = \frac{A}{2}$ ; $\delta_2 = \left(\frac{9}{8} - 1\right)A = \frac{A}{8}$
$\delta_1 : \delta_2 = 4 : 1$ , so the answer is (d).

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Prism, Dispersion & Scattering question from MHT CET 2023 (14 May, Shift 1)

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