The angle of deviation through a prism is minimum when (A) Incident ray and emergent ray are symmetric to the prism. (B) The refracted ray inside the prism becomes parallel to its base (C) Angle of incidence is equal to that of the angle of emergence (D) When angle of emergence is double the angle of incidence Choose the correct answer from the options given below: (a) Statements (B) and (C) are true (b) Only statements (A) and (B) are true (c) Statements (A), (B) and (C) are true (d) Only statement (D) is true

Answer: (c). At minimum deviation r₁ = r₂, so the ray inside is parallel to the base: (B) true. Then i = e: (C) true, and the incident and emergent rays are symmetric about the prism: (A) true. (D) is false, e = i, not 2i. So the answer is (c) A, B and C are true.

The angle of deviation through a prism is minimum when (A) Incident… | JEE Main 2021 (16 Mar, Shift 1)

Q56JEE Main 2021 · 16 MAR · SHIFT 1Easy

Prism, Dispersion & Scattering

The angle of deviation through a prism is minimum when

(A) Incident ray and emergent ray are symmetric to the prism.

(B) The refracted ray inside the prism becomes parallel to its base

(D) When angle of emergence is double the angle of incidence

Choose the correct answer from the options given below:

Show answer and solution

Answer: (c)

At minimum deviation $r_1 = r_2$ , so the ray inside is parallel to the base: (B) true.
Then $i = e$ : (C) true, and the incident and emergent rays are symmetric about the prism: (A) true.
(D) is false, $e = i$ , not $2i$ .
So the answer is (c) A, B and C are true.

Report a mistake

Prism, Dispersion & Scattering question from JEE Main 2021 (16 Mar, Shift 1)

More questions on Prism, Dispersion & Scattering