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JEE Main 2024 (8 Apr, Shift 2) · Time of Flight, Maximum Height & Range

Time of Flight, Maximum Height & Range question from JEE Main 2024 (8 Apr, Shift 2)

Q12JEE Main 2024 · 8 APR · SHIFT 2Easy

Time of Flight, Maximum Height & Range

The angle of projection for a projectile to have same horizontal range and maximum height is:

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Answer: (d)

  1. RH=4tan⁡θ\frac{R}{H} = \frac{4}{\tan\theta}
  2. R=H⇒tan⁡θ=4R = H \Rightarrow \tan\theta = 4
  3. So the answer is (d) tan⁡−1(4)\tan^{-1}(4).
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