The angle subtended by the vector A = 4i + 3j + 12k with the X -axis is (a) cos ⁻¹(3/13) (b) sin ⁻¹(3/13) (c) sin ⁻¹(4/13) (d) cos ⁻¹(4/13)

Answer: (d). |A| = √(16 + 9 + 144) = 13 cos α = (Ax)/(|A|) = 4/13 So the answer is (d) cos ⁻¹(4/13).

The angle subtended by the vector A = 4i + 3j + 12k with the X -axis… | MHT CET 2020 (19 Oct, Shift 2)

Q16MHT CET 2020 · 19 OCT · SHIFT 2Easy

Vector Basics, Unit Vectors & Components

The angle subtended by the vector $A = 4\hat{i} + 3\hat{j} + 12\hat{k}$ with the $X$ -axis is

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Answer: (d)

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