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MHT CET 2025 (5 May, Shift 2) · Rotational Kinetic Energy, Work & Power

Rotational Kinetic Energy, Work & Power question from MHT CET 2025 (5 May, Shift 2)

Q14MHT CET 2025 · 5 MAY · SHIFT 2Medium

Rotational Kinetic Energy, Work & Power

The angular momentum of a rotating body is ' $L$ '. When the frequency of rotating body is tripled and its kinetic energy is made one-third, the new angular momentum becomes

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Answer: (a)

$L = \frac{2K}{\omega}$ (since $K = \frac{1}{2}L\omega$ )
$L' = \frac{2(K/3)}{3\omega} = \frac{L}{9}$
So the answer is (a) $\frac{1}{9}L$ .

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