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MHT CET 2026 (20 Apr, Shift 1) · Bohr Model: Orbits, Speed & Angular Momentum

Bohr Model: Orbits, Speed & Angular Momentum question from MHT CET 2026 (20 Apr, Shift 1)

Q13MHT CET 2026 · 20 APR · SHIFT 1Medium

Bohr Model: Orbits, Speed & Angular Momentum

The angular momentum of an electron in Bohr's hydrogen atom having energy $(-0.544)$ eV is ( $h$ = Planck's constant)

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Answer: (c)

$E_n = -\frac{13.6}{n^2}\text{ eV}$ : $n^2 = \frac{13.6}{0.544} = 25$ , so $n = 5$ .
$L = \frac{nh}{2\pi} = \frac{5h}{2\pi}$
So the answer is (c) $\frac{5h}{2\pi}$ .

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