The angular momentum of an electron moving in an orbit of hydrogen atom is 1.5(h/π). The energy in the same orbit is nearly. (a) -1.5 eV (b) -1.6 eV (c) -1.3 eV (d) -1.4 eV

Answer: (a). L = (nh)/(2π); given L = 1.5 h/π = (3h)/(2π), so n = 3. E₃ = (-13.6)/(9) = -1.51 eV So the answer is (a) -1.5 eV.

The angular momentum of an electron moving in an orbit of hydrogen… | NEET 2023

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Energy of the Electron & Energy Levels

The angular momentum of an electron moving in an orbit of hydrogen atom is $1.5\left(\frac{h}{\pi}\right)$ . The energy in the same orbit is nearly.

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Answer: (a)

$L = \frac{nh}{2\pi}$ ; given $L = 1.5\,\frac{h}{\pi} = \frac{3h}{2\pi}$ , so $n = 3$ .
$E_3 = \frac{-13.6}{9} = -1.51$ eV
So the answer is (a) $-1.5$ eV.

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