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JEE Main 2021 (17 Mar, Shift 1) · Rotational Kinematics & Dynamics

Rotational Kinematics & Dynamics question from JEE Main 2021 (17 Mar, Shift 1)

Q38JEE Main 2021 · 17 MAR · SHIFT 1Easy

Rotational Kinematics & Dynamics

The angular speed of truck wheel is increased from 900 rpm to 2460 rpm in 26 seconds. The number of revolutions by the truck engine during this time is _____________. (Assuming the acceleration to be uniform).

Numerical answer type. Work it out, then open the answer.

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Answer: 728

900 rpm $= 15$ rev/s, 2460 rpm $= 41$ rev/s
Revolutions $= \frac{15 + 41}{2} \times 26 = 28 \times 26 = 728$
So the number of revolutions is 728.

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