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NEET 1991 (AIPMT) · Simple Pendulum

Simple Pendulum question from NEET 1991 (AIPMT)

Q91NEET 1991 · AIPMTEasy

Simple Pendulum

The angular velocity and the amplitude of a simple pendulum is $\omega$ and $a$ respectively. At a displacement $x$ from the mean position if its kinetic energy is $T$ and potential energy is $V$ , then the ratio of $T$ to $V$ is

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Answer: (c)

$T = \frac{1}{2}m\omega^2(a^2 - x^2)$ and $V = \frac{1}{2}m\omega^2x^2$ .
$\frac{T}{V} = \frac{a^2 - x^2}{x^2}$
So the answer is (c).

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