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NEET 2015 (AIPMT, Cancelled Paper) · Bulk Modulus & Compressibility

Bulk Modulus & Compressibility question from NEET 2015 (AIPMT, Cancelled Paper)

Q21NEET 2015 · AIPMT · CANCELLED PAPERMedium

Bulk Modulus & Compressibility

The approximate depth of an ocean is 2700 m. The compressiblity of water is 45.4 ×\times 10−11 Pa−1 and density of water is 103 kg/m3. What fractional compression of water will be obtained at the bottom of the ocean?

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Answer: (a)

  1. ΔVV=compressibility×P\frac{\Delta V}{V} = \text{compressibility}\times P, with P=ρghP = \rho g h.
  2. P=103×9.8×2700=2.646×107 PaP = 10^{3}\times9.8\times2700 = 2.646\times10^{7}\ \text{Pa}
  3. ΔVV=45.4×10−11×2.646×107≈1.2×10−2\frac{\Delta V}{V} = 45.4\times10^{-11}\times2.646\times10^{7} \approx 1.2\times10^{-2}
  4. So the answer is (a).
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