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JEE Main 2022 (24 Jun, Shift 1) · Acceleration Due to Gravity

Acceleration Due to Gravity question from JEE Main 2022 (24 Jun, Shift 1)

Q81JEE Main 2022 · 24 JUN · SHIFT 1Medium

Acceleration Due to Gravity

The approximate height from the surface of earth at which the weight of the body becomes 13\frac{1}{3} of its weight on the surface of earth is:

[Radius of earth R = 6400 km and 3\sqrt{3} = 1.732]

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Answer: (b)

  1. W′W=(RR+h)2=13\frac{W'}{W} = \left(\frac{R}{R+h}\right)^2 = \frac{1}{3}
  2. R+h=3R⇒h=(3−1)RR + h = \sqrt{3}R \Rightarrow h = (\sqrt{3}-1)R
  3. h=0.732×6400≈4685h = 0.732 \times 6400 \approx 4685 km
  4. So the answer is (b) 4685 km.
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