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JEE Main 2022 (26 Jul, Shift 2) · Thermal Stress & Breaking Stress

Thermal Stress & Breaking Stress question from JEE Main 2022 (26 Jul, Shift 2)

Q7JEE Main 2022 · 26 JUL · SHIFT 2Easy

Thermal Stress & Breaking Stress

The area of cross section of the rope used to lift a load by a crane is 2.5×10−4 m22.5 \times 10^{-4}\text{ m}^2. The maximum lifting capacity of the crane is 10 metric tons. To increase the lifting capacity of the crane to 25 metric tons, the required area of cross section of the rope should be:

(take g=10 ms−2g = 10\text{ ms}^{-2})

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Answer: (a)

  1. Breaking stress is fixed, so the required area is proportional to the load: A∝WA \propto W.
  2. A2=2.5×10−4×2510=6.25×10−4 m2A_2 = 2.5 \times 10^{-4} \times \dfrac{25}{10} = 6.25 \times 10^{-4}\text{ m}^2
  3. So the answer is (a) 6.25×10−4 m26.25 \times 10^{-4}\text{ m}^2.
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