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MHT CET 2026 (15 Apr, Shift 2) · Pressure & Kinetic Energy of a Gas

Pressure & Kinetic Energy of a Gas question from MHT CET 2026 (15 Apr, Shift 2)

Q7MHT CET 2026 · 15 APR · SHIFT 2Difficult

Pressure & Kinetic Energy of a Gas

The average translational kinetic energy of a molecule in a gas is E1E_1. The kinetic energy of the electron (e) accelerated from rest through potential difference 'V' volt is E2E_2. The temperature at which E1=E2E_1 = E_2 possible is (N = number of molecules, R = gas constant)

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Answer: (b)

  1. E1=32kBT=32RNTE_1 = \frac{3}{2}k_BT = \frac{3}{2}\frac{R}{N}T and E2=eVE_2 = eV.
  2. E1=E2⇒T=2eVN3RE_1 = E_2 \Rightarrow T = \frac{2eVN}{3R}
  3. So the answer is (b) 2eVN3R\frac{2eVN}{3R}.
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